5x^2-16x+20=0

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Solution for 5x^2-16x+20=0 equation:


Simplifying
5x2 + -16x + 20 = 0

Reorder the terms:
20 + -16x + 5x2 = 0

Solving
20 + -16x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
4 + -3.2x + x2 = 0

Move the constant term to the right:

Add '-4' to each side of the equation.
4 + -3.2x + -4 + x2 = 0 + -4

Reorder the terms:
4 + -4 + -3.2x + x2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -3.2x + x2 = 0 + -4
-3.2x + x2 = 0 + -4

Combine like terms: 0 + -4 = -4
-3.2x + x2 = -4

The x term is -3.2x.  Take half its coefficient (-1.6).
Square it (2.56) and add it to both sides.

Add '2.56' to each side of the equation.
-3.2x + 2.56 + x2 = -4 + 2.56

Reorder the terms:
2.56 + -3.2x + x2 = -4 + 2.56

Combine like terms: -4 + 2.56 = -1.44
2.56 + -3.2x + x2 = -1.44

Factor a perfect square on the left side:
(x + -1.6)(x + -1.6) = -1.44

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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